Characterization of polymeric materials.

 

 

 

 

1) Discuss numerous methods to characterize the properties of polymers and of the materials
formed by polymers.
Match each of the scenarios below with the most appropriate technique by choosing a method from
the box below, and explain your answer. Each method may be matched to only one scenario, so
choose wisely!
a) You are measuring the properties of fibers of poly(paraphenylene terephthalamide), branded
Kevlar, under mechanical stress. To determine how the crystalline orientation of the polymers
change with applied stress, what technique would be best? (4 points)
b) You have synthesized a block copolymer and need to assess the polydispersity of your
synthesized product. What technique would be best? (4 points)
c) You need to assess the structures of spherulites formed in a semicrystalline polypropylene
sample. What technique would be best? (4 points)
d) You need to determine the glass transition temperature of a sample of polycarbonate. What
technique would be best? (4 points)
e) You have fabricated a thin polymer membrane with 10 nm pores for filtration and need to assess
the uniformity of pore size. Which technique would be best? (4 points)
transmission electron microscopy (TEM), wide-angle X-ray scattering (WAXS),
gel permeation chromatography (GPC), atomic force microscopy (AFM),
differential scanning calorimetry (DSC)
MSE 151: Polymeric Materials Prof. Stacy Copp
UC Irvine Materials Science and Engineering
© Stacy Copp 2020
2. Improving strength with polymer blending. (18 points total)
The figure below displays stress-strain curves for poly(lactic acid) (PLA, black), poly(methyl
methacrylate) (PMMA, red), polybutadiene-g-poly(styrene-co-acrylonitrile) (PB-g-SAN, dark
red), and blends of these polymers (green, pink, and blue curves). For each blend, the two polymers
in the blend are separated by a slash (/).
a) PLA is a biodegradable polymer which can be sourced from renewable feedstocks, but PLA
has mechanical shortcomings, as shown by the black stress-strain curve above.
(i) What type of failure is PLA exhibiting? (2 points)
(ii) What does this suggest about the degree of crystallinity of PLA? In other words, is PLA
likely to be amorphous or crystalline? (2 points)
b) Which of the curves above is an elastomer? How can you tell? (4 points)
c) Which of the polymer blends displays ductile deformation? How can you tell? (4 points)
d) Estimate �!” and �!” at the onset of necking for the PMMA/PB-g-SAN blend. (4 points)
e) DSC of both PLA and PLA/PB-g-SAN show a crystallization transition. Adding PMMA
(which is amorphous) into the blend makes the material significantly more resistant to fracture.
Given that the tri-blend PLA/PMMA/PB-g-SAN is more resistant to fracture, would you expect
DSC measurements to observe a crystallization transition or not? (2 points)
MSE 151: Polymeric Materials Prof. Stacy Copp
UC Irvine Materials Science and Engineering
© Stacy Copp 2020
3) Polymeric materials: states of matter
(19 points total)
a) Crystalline and amorphous polymers.
(i) Which graph corresponds to a semicrystalline polymeric material (right)?
Explain your answers in the context of
phase transition thermodynamics. (3 points)
(ii) Which graph corresponds to an amorphous polymeric material? Explain your answers in the
context of phase transition thermodynamics. (3 points)
(iii) On graphs (1) and (2) above, mark the glass transition temperature Tg or the melting
temperature Tm, depending on which is relevant for each type of polymeric material. (4 points)
b) Rate of cooling. The graph to the right shows volume of a polymeric
material as it is cooled from a liquid state to a glassy state at three
different cooling rates a, b, and c.
(i) Which curve corresponds to the slowest rate of cooling? How can you
tell? (2 points)
(ii) Why does V(T) depend on the cooling rate for glassy polymeric
materials? (2 points)
c) Thermal cycling. Consider a semi-crystalline polymeric material with crystallinity �# at
temperature T1 below the melting temperature, Tm.
(i) This polymer is heated up to T2 (T1 < T2 < Tm), and held at constant T2 for a certain time before
cooling back to T1. On the graph below (or a graph you draw yourself), sketch �(�) for this
polymeric material over the entire thermal cycle, from T1 to T2 and back to T1. (3 points)
(ii) Does the final crystallinity increase or decrease after
thermal cycling? Why? (2 points)
MSE 151: Polymeric Materials Prof. Stacy Copp
UC Irvine Materials Science and Engineering
© Stacy Copp 2020
4) Nucleation of polymer crystals. (22 points total) The change in free energy ∆� upon formation
of a crystalline nucleus within an amorphous polymer is:
∆� = ��
� (�$ − �#) + ��
� and � are volume and surface area of the nucleus, respectively; � and � are density and
molecular weight of the material, respectively; �# is molar free energy of the liquid polymer; �$
is molar free energy of the crystalline polymer; � is coefficient of surface tension.
Most polymers crystallize into thin layers like
the diagram below of a square “lamella” with
side length ℓ and thickness ℎ. Because the
sides (shown by the green squiggly lines) and
the top/bottom of the crystal have different
crystalline planes, the coefficient of surface
tension of the top and bottom, �%&’, differs from that of the sides, �()*+.
a) Write an expression for ∆� of this lamella in terms of ℓ and ℎ. (6 points)
b) In this case, ∆� is a function of both ℓ and ℎ, and there exist some critical point(s) (ℓ∗, ℎ∗) for
which ∆� is a local maximum. Derive the critical length and thickness of the nucleus, (ℓ∗, ℎ∗), and
state which values of ℓ∗, ℎ∗ are physically relevant (8 points)
c) Write an expression for the corresponding height of the energy barrier at this critical point, ∆�∗,
in terms of �%&’ and �()*+. (Simplify this expression – don’t just write a messy answer!) (4 points)
d) Now write ∆�∗ in terms of ℓ∗ and/or ℎ∗. (Note: you can pick multiple ways to do this.) What
does your expression tell you about how the height of the energy barrier relates to one of the terms
in the expression for (a) above? (Hint: see lecture on this topic for example of how this was done
for a spherical nucleus.) (4 points)
MSE 151: Polymeric Materials Prof. Stacy Copp
UC Irvine Materials Science and Engineering
© Stacy Copp 2020
5. Polymer blends and composites. (16 pointstotal) Flory-Huggins theory can be used to describe
how a polymer dissolves in a solvent (as discussed in lecture) and can also be used to predict
whether two different polymers will form a miscible blend or will phase-separate upon mixing.
a) What must be true about the change in Gibbs free energy upon blending two polymers if the
two polymers are miscible? (3 points)
b) Consider a mixture of n1 moles of polymer 1 with volume fraction �# and n2 moles of
polymer 2 with volume fraction �$. Write the expression for the change in entropy ∆� upon
mixing two polymers together. (3 points)
c) For polymer blends, the enthalpy of mixing can be expressed as �#�$� (this differs slightly
from the case of a polymer dissolved in a solvent). � is the Flory-Huggins parameter which
describes the interaction between polymers 1 and 2. Write the expression for the change in Gibbs
free energy upon mixing. (4 points)
d) What is the sign (positive or negative) of the two entropic terms in ∆�? Why? (3 points)
e) The point at which miscibility becomes possible for a polymer blend is called �-.)%. Derive an
expression for �-.)% for polymers 1 and 2, using your answer from (c). (3 points)

 

 

Sample Solution

between Hamlet’s thoughts and actions but we once again see proof of Eric Levy’s theory of the relation between reason and emotion in the world of this play. When Hamlet proclaims his love for Ophelia was greater than that of “forty thousand brothers,” Claudius quickly points to Hamlet’s madness as a cause for this emotional and dramatic outburst. But, just as before, Hamlet is not mad but rather knows precisely what he is doing. He is, at last, ready to perform his role in the face of his own death. In the final scene of the play, Hamlet’s mind is the clearest is has been and his thoughts are incredibly rational. He is now more metatheatrically aware than he has been at any other point in the entire play and he reveals this in his discourse with Horatio. He tells Horatio exactly what happened on his trip to England and reveals Claudius’ plot to have him murdered. His tale is laced with super-awareness and a very broad sense of his condition when he praises impulsive behavior because “there’s a divinity that shape’s our ends, rough-hew them how we will” (Shakespeare V.ii.11-12). He recognizes the inevitability of his fate and the futility of deep reflection about life to try to change its outcome. He understands that the only way to incite change is through action and no matter how you try to paint life in your mind, it will not change. Throughout the following dialogue, Hamlet mixes in many more theatrical metaphors to describe his situation. He alludes to the fact that he has finally begun his performance after the very detailed research he performed throughout the rest of the play. The play ends with Hamlet’s death and possibly the clearest thought we’ve seen from him since the beginning of the play. Hamlet instructs Horatio to tell his story and to crown the invading Fortinbras king of Denmark. Hamlet is ready to take his fin

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