Absolutely! Let’s analyze the scenario to find the probability of drawing a red marble followed by a blue marble without replacing them.

We can approach this problem by considering the probability of each event happening sequentially.

1. Probability of drawing a red marble first:

   • There are 5 red marbles out of a total of (5 + 3 + 2) = 10 marbles.
   • So, the probability of picking a red marble first is 5/10.

2. Probability of drawing a blue marble second (after taking out a red marble):

   • Since we’re not replacing the marbles, there are only 9 marbles left after taking out the red one.
   • Out of the remaining 9 marbles, there are still 3 blue marbles.
   • Therefore, the probability of picking a blue marble after taking out a red marble is 3/9.

Now, to get the overall probability of both events happening (red first, then blue), we multiply these two probabilities:

(Probability of red) * (Probability of blue after red) = (5/10) * (3/9)

This simplifies to 1/6.

Therefore, the probability of drawing a red marble followed by a blue marble without replacement is 1/6.